package genstack

// GenStack implements a generational stack.
//
// GenStack works as common stack except for the fact that all elements in the
// older generation are guaranteed to be popped before any element in the newer
// generation. New elements are always pushed to the current (newest)
// generation.
//
// We could also say that GenStack behaves as a stack in case of a single
// generation, but it behaves as a queue of individual generation stacks.
type GenStack[ any] struct {
	// We can represent arbitrary number of generations using 2 stacks. The
	// new stack stores all new pushes and the old stack serves all reads.
	// Old stack can represent multiple generations. If old == new, then all
	// elements pushed in previous (not current) generations have already
	// been popped.

	old *stack[]
	new *stack[]
}

// NewGenStack creates a new empty GenStack.
func [ any]() *GenStack[] {
	 := &stack[]{}
	return &GenStack[]{
		old: ,
		new: ,
	}
}

func ( *GenStack[]) () (, bool) {
	// Pushes always append to the new stack, so if the old once becomes
	// empty, it will remail empty forever.
	if .old.len() == 0 && .old != .new {
		.old = .new
	}

	if .old.len() == 0 {
		var  
		return , false
	}

	return .old.pop(), true
}

// Push pushes a new element at the top of the stack.
func ( *GenStack[]) ( ) { .new.push() }

// NextGen starts a new stack generation.
func ( *GenStack[]) () {
	if .old == .new {
		.new = &stack[]{}
		return
	}

	// We need to pop from the old stack to the top of the new stack. Let's
	// have an example:
	//
	//   Old: <bottom> 4 3 2 1
	//   New: <bottom> 8 7 6 5
	//   PopOrder: 1 2 3 4 5 6 7 8
	//
	//
	// To preserve pop order, we have to take all elements from the old
	// stack and push them to the top of new stack:
	//
	//   New: 8 7 6 5 4 3 2 1
	//
	.new.push(.old.takeAll()...)

	// We have the old stack allocated and empty, so why not to reuse it as
	// new new stack.
	.old, .new = .new, .old
}

// Len returns number of elements in the stack.
func ( *GenStack[]) () int {
	 := .old.len()
	if .old != .new {
		 += .new.len()
	}

	return 
}